Don't agree with this one.
func foo(a: Int = 0, b: Int = 1, c: Int = 2) {
print(a, b, c)
}
foo(a: 1, c: 3)
let bar = foo
bar(1, 3) will different than foo(a: 1, c: 3)
> 在 2016年7月7日，11:06，Chris Lattner <[email protected]> 写道：
>
> Proposal Link:
> https://github.com/apple/swift-evolution/blob/master/proposals/0111-remove-arg-label-type-significance.md
>
> The review of "SE-0111: Remove type system significance of function argument
> labels " ran from June 30 ... July 4, 2016. The proposal has been *accepted*:
>
> The community and core team agree that this proposal will lead to a
> simplification and clarification of the type system, as well as a more clear
> user model for parameter labels. In response to community feedback, the core
> team is accepting the proposal with a revision to allow “purely cosmetic”
> parameter labels in closure types for documentation (as outlined in the
> alternatives section). The core team also wants to clarify that a call to a
> value of closure type would not allow use of any parameter labels, some
> interpretations thought that “arbitrary” parameter labels could be used.
>
> Thank you to Austin Zheng for driving this discussion forward! I filed
> SR-2009 to track implementation work on this.
>
> -Chris Lattner
> Review Manager
>
> _______________________________________________
> swift-evolution-announce mailing list
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