This is something additional, but I’m curios about how the community feels
about it.
I recently come across the issue where conforming to Hashable wasn’t enough to
thecke if two instances of the same generic type were equal.
I had additionally provide myself the != function.
public func !=<T, U>(lhs: SomeTypeName<T>, rhs: SomeTypeName<U>) -> Bool {
return lhs.hashValue != rhs.hashValue
}
I wondered if Swift can ever get generic specialization like this:
public func !=<T : Hashable, U, V>(lhs: T<U>, rhs: T<V>) -> Bool {
return !(lhs.hashValue == rhs.hashValue)
}
This function in stdlib would fill the gap. Or we need an extra protocol
GenericHashable which includes !=.
--
Adrian Zubarev
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