On 20 Sep 2016, at 18:43, Nevin Brackett-Rozinsky via swift-evolution
<[email protected] <mailto:[email protected]>> wrote:
I have been following this discussion (as well as similar threads earlier
this year) and listening to the ideas put forth by all sides.
It seems to me that the fundamental difference between classes and
protocols is that classes inherit implementation whereas protocol
conformance is a promise about interface.
When a class or struct or enum declares itself as conforming to a
protocol, that means it has all the members specified in the protocol.
The protocol conformance simply codifies a fact about the type itself:
namely that all those members are present.
In this model, any keyword such as `implements` on each conforming member
would introduce substantial boilerplate for negligible gain. The purpose
of a protocol is to communicate that certain members are available, not
to make declaring those members more onerous.
However, default implementations for protocols blur the line. Now there
is actual implementation being inherited. A conforming type may choose to
roll its own version of a method, or to utilize the default provided by
the protocol. This is closer to the situation with subclassing.
Moreover, a protocol which conforms to another protocol may itself define
(or redefine!) default implementations for members of that other
protocol. This can create “inheritance chains” of protocol default
implementations. I think there is value in being able to refer to (and
call) the inherited default implementation through some sort of `super`
functionality.
On the other hand, the existence of a default implementation in a
protocol is in large part merely a convenience: a courtesy so that each
conforming type need not rewrite the same boilerplate code.
A type which conforms to a protocol may accept the default or it may
provide its own implementation, but it is not “overriding” anything. The
default implementation was offered as a convenience, to be taken or left
as needed. Thus I do not think any keyword (neither `override` nor
`implements`) should be required in that case either.
The frequently-raised point regarding near-miss member names deserves
some attention. Several people have expressed a desire for the compiler
to assist them in determining whether a given member does or does not
meet a protocol requirement. Specifically, when a type conforms to a
protocol with a default implementation, and the type defines a member
with a similar signature, it is not obvious at glance if that member
matches the protocol.
I think this is a job for linters and IDEs. For example, syntax
highlighting could distinguish members which satisfy a protocol
requirement, thereby providing immediate visual confirmation of success.
Having followed the lengthy discussion and weighed the numerous ideas put
forth, I come down firmly on the side of no keyword for protocol conformance.
A protocol describes an interface and provides a set of customization
points. It may also, as a convenience, offer default implementations. The
protocol simply describes the capabilities of its conforming types, and
any default implementations are there to make things easier for them.
Conforming types should not be afflicted with extraneous keywords: that
would run contrary to the purpose of having protocols in the first place.
Nevin
On Tue, Sep 20, 2016 at 11:16 AM, Xiaodi Wu via swift-evolution
<[email protected] <mailto:[email protected]>> wrote:
As I mentioned above, I agree that better diagnostics for near-misses
are necessary, but they are possible without new syntax. There is no
win in avoiding unintentional behavior because, without a default
implementation, these issues are caught at compile time already.
On Tue, Sep 20, 2016 at 10:14 Vladimir.S via swift-evolution
<[email protected] <mailto:[email protected]>> wrote:
> extension P {
> implement func foo() -> [String : String] { return [:] }
> }
Yes, it seems like we need `implement` (or `override` as another
suggestion) in protocol extension also just for the same reasons
- be clear
about our intention regarding implementing the requirement, to
show that
this func *depends* on the previous definition of P protocol and
to avoid
possible mistakes related to protocol conformance.
On 20.09.2016 17:38, Charles Srstka wrote:
>> On Sep 20, 2016, at 8:17 AM, Vladimir.S via swift-evolution
>> <[email protected] <mailto:[email protected]>
<mailto:[email protected]
<mailto:[email protected]>>> wrote:
>>
>> On 20.09.2016 3:03, Xiaodi Wu via swift-evolution wrote:
>>> I definitely think Vladimir's suggestion is a great starting
point, IMO.
>>>
>>> However, I think it could be improved in one key respect
where previous
>>> proposals using `override` are superior. Namely, the proposed
`implement`
>>> keyword adds no additional safety when a type implements a
protocol
>>> requirement that doesn't have a default implementation. This
is because, if
>>
>> Yes, *at the moment of writing* the type's code there could be
no default
>> implementation for protocol requirement. But, *at the moment of
>> compilation* such default implementation could appear.
>>
>> Let's discuss such scenario in case we'll take your suggestion:
>>
>> You got SomeClass.swift file, 3rd party file you don't want to
change or
>> changes are not allowed. Content:
>>
>> public protocol SomeProtocol {
>> func foo()
>> }
>>
>> public class SomeClass : SomeProtocol {
>> func foo() {...} // no default implementation *at the moment
of writing*,
>> no need in `overload`
>> }
>>
>> Now, you adds SomeClass.swift file to your project and in some
*other*
>> file you write:
>>
>> extension SomeProtocol {
>> func foo() {...}
>> }
>>
>> As you see, you don't control the SomeClass.swift but you
suggest in this
>> case SomeClass.foo() should be defined with `override`.
>>
>> With 'implement' SomeClass.foo() will be marked initially and
will save
>> us if protocol's requirement PLUS default implementation changed.
>
> Requiring the ‘implement’ keyword can help us even if no default
> implementation is involved. Consider:
>
> protocol P {
> func foo() -> [String : Any]
> }
>
> struct S : P {
> func foo() -> [String : String] { return [:] }
> }
>
> We will get an error here that S does not conform to P.
However, this is
> not the correct error, since S in fact *tries* to conform to P,
but it has
> a mistake in a method signature. This misleads us as to the
true nature of
> the problem, and if S has enough members in it that we fail to
spot the
> existing foo(), we might solve the problem by reimplementing
foo(), and
> leaving the original foo() as dangling dead code. Having an
‘implement’
> keyword on the existing foo() function would change the
compiler error to
> let us know that we have an existing foo() that is incorrectly
declared.
>
> In addition, ‘implement’ can help us when the declaration in
question *is*
> the default implementation:
>
> protocol P {
> func foo() -> [String : Any]
> }
>
> extension P {
> implement func foo() -> [String : String] { return [:] }
> }
>
> Here we will get an error with the proposed ‘implement’
keyword, because
> foo() does not have a signature matching anything in the
protocol, whereas
> without ‘implement’ we would happily and silently generate a
useless
> dangling function that would never be used, and then pass the
buck to the
> concrete type that implements P:
>
> protocol P {
> func foo() -> [String : Any]
> }
>
> extension P {
> func foo() -> [String : String] { return [:] } // The error is
here:
> }
>
> struct S : P {} // But it gets reported here.
>
> Charles
>
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