The way I want things to work, “super” always calls the superclass’s method with matching name and signature.
For the scenario you outlined, the superclass defines such a method, so it gets called. For the situation relevant to this proposal, if the superclass *obtains* such a method via default implementation of a protocol requirement, I want exactly the same thing to happen. Namely, when the subclass’s override calls “super”, I want the superclass’s method with identical name and signature to be invoked. It does not matter where the superclass *got* that method, all that matters is the superclass *has* such a method, in which case it gets called. Nevin
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