On 24/04/2017 10:42, Jonathan Hull wrote:
You can also do:

switch self {
   case .Int: return "int"
   case .Fun(.Fun(let p), let r): return "(\(p)) -> \(r)"
   case .Fun(let p, let r): return "(\(p) -> \(r))"
}

I didn't know you can do that and it seems consistent with other features of the language. However, it doesn't do what I was aiming for. In your example `p` will be bound to a `(Type, Type)`, not a `Type`. So the string result, instead of being `(int -> int) -> int` is actually `((int, int)) -> int`.

Anyway, I've learned something new, so thanks!


On Apr 23, 2017, at 6:55 AM, Ionuț G. Stan via swift-evolution 
<[email protected]> wrote:

Hi all,

I'm unsure if this is the appropriate venue to discuss this, so apologies if 
it's not.

I was wondering if the issue of supporting as-patterns in switch statements has 
been brought up before or not, and what was the outcome of that.

By as-patterns I mean the ability to bind sub-patterns to identifiers. See this 
question of mine on StackOverflow for an example: 
http://stackoverflow.com/questions/43566117/haskell-like-as-patterns-in-swift/43567041#43567041

Maybe an equal sign could be used to denote that, so my example above would 
become:

   switch self {
   case .Int: return "int"
   case .Fun(let p = .Fun, let r): return "(\(p)) -> \(r)"
   case .Fun(let p, let r): return "(\(p) -> \(r))"
   }

Note the `let p = .Fun` part.

Alternatively, enhancing the `where` clause of a `case` to support the same 
features as an `if case` expression, would be an acceptable choice, too?

   case .Fun(let p, let r) where case .Fun = p:
       return "(\(p)) -> \(r)"

Thanks for reading.

--
Ionuț G. Stan  |  http://igstan.ro  |  http://bucharestfp.ro
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--
Ionuț G. Stan  |  http://igstan.ro  |  http://bucharestfp.ro
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