Back to the initial example, here’s a variant that shows a “non-mutable”
pointer lying; try it in a playground.
```
func get(_ pointer: UnsafePointer<Int>, at index: Int) -> Int
{
let mutator = UnsafeMutablePointer(mutating: pointer)
mutator[index] += 1
return pointer[index]
}
let constantArray = [Int](repeating: 0, count: 3)
print(constantArray) // [0,0,0]
let mutated = get(constantArray, at: 2) // returns 1
print(constantArray) // [0,0,1] oops!
```
I’d argue that this case should also require an ampersand and a mutable array.
Cheers,
Guillaume Lessard
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