Hi all,
Could someone please tell me why the following fails?
func foo(f: () throws -> () = {}) rethrows {
try f()
}
// Fine
foo({ })
// This fails with error:
// call is to 'rethrows' function,
// but a defaulted argument function can throw
foo()
Why should I have to write "try foo()", shouldn't it take the default value
(non throwing closure)?
Regards,
Bhargav Gurlanka
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