So this:
if let data = someArrayGeneratingFunction() {
cFunction(UnsafeMutablePointer(data))
}
Has issues with the array passed to c getting corrupted, but this doesn't:
let data = someArrayGeneratingFunction()
if let data = data {
cFunction(UnsafeMutablePointer(data))
}
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On 28 July 2016 at 21:32, Dmitri Gribenko <griboz...@gmail.com> wrote:
> On Thu, Jul 28, 2016 at 1:27 PM, James Campbell via swift-users
> <swift-users@swift.org> wrote:
> > How are arrays passed to C in Linux ? I tried unwrapping an optional
> array
> > in an if statment and passing it to c. it seemed like the array was
> > deallocated however if I stored it in a local var in the function before
> the
> > if statment it worked perfectly fine, sureley this shouldn't work either
> ?
>
> Would you mind pasting the code example?
>
> Dmitri
>
> --
> main(i,j){for(i=2;;i++){for(j=2;j<i;j++){if(!(i%j)){j=0;break;}}if
> (j){printf("%d\n",i);}}} /*Dmitri Gribenko <griboz...@gmail.com>*/
>
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