Why not define some other symbol so that you can get the precedence you want?
-- Howard. On 30 November 2016 at 09:28, Greg Parker via swift-users < swift-users@swift.org> wrote: > > > On Nov 29, 2016, at 2:55 AM, Rick Mann via swift-users < > swift-users@swift.org> wrote: > > > > Working on dimensional analysis, I have some proof-of-concept code that > seems to be working: > > > > let n1 = kilogram * meter / second * second > > ([(kg⋅m) / s]⋅s) > > > > let n2 = kilogram * meter / (second * second) > > [(kg⋅m) / (s⋅s)] > > > > Note: () around unit products, [] around unit quotients. > > > > I'd like to adjust the precedence of operator * for my Unit protocol to > be higher than /. Is that possible? It wasn't at all clear to me how to do > that in Swift 3, or if can even be done at all. > > You can't. A Swift operator's precedence is the same for all types that > implement that operator. Operators * and / cannot use the same precedence > on Int but different precedence on Unit. > > You could try to change the precedence of * and / globally - they're > defined like any other operator in stdlib/public/core/Policy.swift - but > you'll break lots of other code that way. > > > -- > Greg Parker gpar...@apple.com Runtime Wrangler > > > _______________________________________________ > swift-users mailing list > swift-users@swift.org > https://lists.swift.org/mailman/listinfo/swift-users >
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