IMO the error message says it all:
Playground execution failed: error: MyPlayground8.playground:9:5: error: cannot
invoke 'foo' with an argument list of type '(P)'
foo(x)
^
MyPlayground8.playground:9:5: note: expected an argument list of type '(A)'
foo(x)
^
I.e. you are passing in a protocol while the function is specified for a type.
Said other way: On which data do you expect the protocol to operate?
Regards,
Rien
Site: http://balancingrock.nl
Blog: http://swiftrien.blogspot.com
Github: http://github.com/Swiftrien
Project: http://swiftfire.nl
> On 22 Dec 2016, at 17:05, Mikhail Seriukov via swift-users
> <swift-users@swift.org> wrote:
>
> Hello community! I' wondering if somebody can explain this to me.
> Please take look at the snippet.
>
> protocol P {}
> struct X:P {}
>
> func foo<A:P>(_ x:A) {}
>
> func bar() {
> //let x = X() // this compiles
> let x = X() as P // this does not compile. Why?
> foo(x)
> }
>
> I expect the both cases to work though. But only first works? And I do not
> understand why.
> My coworkers said that it is a compiler bug, but I'm not shure it is.
> Thanks for the help.
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