Yes, but why?
What's the rationale for this?
What would be so bad about allowing overriding a non-failable initializer with
a failable initializer?
27. Jan 2017 18:59 by saa...@saagarjha.com:
> You can’t override a designated initializer with one that is failable. The
> second one is defining a new initializer that is failable, instead of
> overriding the one from its superclass.
> Saagar Jha
>
>> On Jan 27, 2017, at 8:45 AM, tuuranton--- via swift-users <>>
>> swift-users@swift.org>> > wrote:
>> >> See the comments. Why is one allowed but the other one isn't
>> and what's the rationale for this?
>>
>> class Vehicle {>> let name: String>> init(name: String) {>>
>> self.name = name>> }>> }
>>
>> class Car: Vehicle {>> //Why is this not allowed?>> override
>> init?(name: String) {>> super.init(name: name)>> }>> >>
>> //But this is allowed?>> init?(name: String, ignore: String) {>>
>> super.init(name: name)>> }>> }
>>
>>
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>
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