Hi,
One of the motivating examples for withoutActuallyEscaping looks like the
following. This predictably doesn’t work because "use of non-escaping
parameter 'predicate' may allow it to escape"
func myFilter(array: [Int], predicate: (Int) -> Bool) -> [Int] {
return Array(array.lazy.filter { predicate($0) })
}
The solution is to use withoutActuallyEscaping. This works and produces the
expected results.
func myFilter(array: [Int], predicate: (Int) -> Bool) -> [Int] {
return withoutActuallyEscaping(predicate) { predicate in
Array(array.lazy.filter({predicate($0)}))
}
}
What I find puzzling is the below example compiles and runs correctly. It seems
like it should be the same compiler error as in the first example.
func myFilter(array: [Int], predicate: (Int) -> Bool) -> [Int] {
return Array(array.lazy.filter(predicate))
}
If you understand why this is so, it would be very helpful.
Thank you and best wishes,
Ray_______________________________________________
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