Hi Slava,
Thanks for your quick response!
I see. That's in line with what I can read from the Type Constraint Syntax
section in the official Swift book.
Satoshi
On Tue, May 2, 2017 at 1:59 AM, Slava Pestov <spes...@apple.com> wrote:
> Hi Satoshi,
>
> Protocols do not conform to themselves. Only concrete types can conform to
> protocols in the current implementation of Swift.
>
> Slava
>
> > On May 2, 2017, at 1:57 AM, Satoshi Nakagawa via swift-users <
> swift-users@swift.org> wrote:
> >
> > Hi,
> >
> > I got a build error "Generic parameter 'T' could not be inferred" for
> the following code.
> >
> > Can anyone explain why we can't use a protocol to infer the generic type
> T?
> >
> > class Emitter {
> > func emit<T: Emittable>() -> T {
> > ...
> > }
> > }
> >
> > protocol Emittable {}
> > protocol Subemittable: Emitable {}
> >
> > class ConcreteEmittable: Subemittable {}
> >
> > func testCode() {
> > let emitter = Emitter()
> >
> > // Error: Generic parameter 'T' could not be inferred
> > let _: Emittable = emitter.emit()
> >
> > // Error: Generic parameter 'T' could not be inferred
> > let _: Subemittable = emitter.emit()
> >
> > // This works
> > let _: ConcreteEmittable = emitter.emit()
> > }
> >
> > Thanks,
> > Satoshi
> >
> > _______________________________________________
> > swift-users mailing list
> > swift-users@swift.org
> > https://lists.swift.org/mailman/listinfo/swift-users
>
>
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