If I write a generic function like this:
func f<T>(_ x: T) { print("Generic: \(x)") }
I can pass it to another function like this:
func g(_ fn: (Int) -> Void) { fn(0) }
g(f) // Prints “Generic: 0”
However if I *also* write a non-generic function like this:
func f(_ x: Int) { print("Int: \(x)") }
Then when I make the same call as before:
g(f) // Prints “Int: 0”
It passes in the new, non-generic version.
Is there something I can do, with both versions of f defined, to pass the
generic f into g?
Nevin
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