Thank you, Adrian.
(What I meant by “debating the correctness of my code” was that I wanted to
talk about the approach and not about the content of the viewDidLoad() method.)
Cheers,
Rick Aurbach
> On Sep 20, 2017, at 3:13 PM, Adrian Zubarev <adrian.zuba...@devandartist.com>
> wrote:
>
> I don’t get your problem here. If you don’t want to debate the correctness of
> your code, why are you asking for help or even showing error messages for a
> code snippet that cannot work?
>
> 1. Drop the access modifier from the extension itself, because this is only
> for convenience, which may or may not rule over the members of the extension
> members. If you’re already explicitly setting the access modifier on the
> extension members then the convenience access modifier makes no sense.
> 2. The code cannot work, because you cannot override `viewDidLoad` on a class
> that you don’t own, on a subclass of `UISplitViewController` that would be
> possible.
>
> ```
> class MySplitViewController : UISplitViewController {}
>
> extension MySplitViewController {
> override open func viewDidLoad() {
> super.viewDidLoad()
> /* ... */
> }
> }
> ```
>
> Am 20. September 2017 um 21:41:31, Rick Aurbach via swift-users
> (swift-users@swift.org <mailto:swift-users@swift.org>) schrieb:
>
>> I am trying to write an extension to a UIKit class, but am running into a
>> can’t-win situation:
>>
>> The code I ‘want’ to write looks like:
>>
>>
>> public extension UISplitViewController {
>> override public func viewDidLoad() {
>> super.viewDidLoad()
>> if UIDevice.current.userInterfaceIdiom == .pad {
>> preferredDisplayMode = .automatic
>> } else {
>> preferredDisplayMode = .primaryOverlay
>> }
>> }
>> }
>>
>> This generates the error message
>> /Users/rlaurb/Projects/Cooks-Memory/Cooks-Memory/AppDelegate.swift:131:23:
>> Overriding instance method must be as accessible as the declaration it
>> overrides
>> /Users/rlaurb/Projects/Cooks-Memory/Cooks-Memory/AppDelegate.swift:131:23:
>> Overridden declaration is here (UIKit.UIViewController)
>>
>> But I can’t change the access control of the function to ‘open’, because I
>> get the warning that the function can’t be “more” accessible than the
>> extension.
>>
>> And I can’t change the extension’s access to ‘open’ because apparently
>> extensions can’t be open.
>>
>> Now I don’t want to get into a debate about whether this code works — it’s
>> just an experiment — but is it even possible to express this idea?? I.e., is
>> it possible to express this idea without subclassing?
>>
>> Cheers,
>>
>> Rick Aurbach
>>
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>> swift-users@swift.org <mailto:swift-users@swift.org>
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