Because it’s being assigned to an ivar, it’s forced to be escaping, or so the
compiler tells me.
-Kenny
> On Jan 5, 2018, at 12:04 PM, Kevin Nattinger <sw...@nattinger.net> wrote:
>
> If you remove the @escaping you'll notice it doesn't complain about a
> non-escaping closure escaping.
> I could be wrong, but I believe that's because using it as an associated
> value forces it to escape on the calling side.
>
> func esc(_ x: @escaping () -> ()) {
> x()
> }
> func noesc(_ x: () -> ()) {
> x()
> }
>
> func foo() {
> noesc {
> print(owner) // compiles
> }
> esc {
> print(owner) // error: requires explicit 'self.'…
> }
> Optional<()->()>.some {
> print(owner) // error: requires explicit 'self.'…
> }
> }
>
>
>> On Jan 5, 2018, at 11:48 AM, Kenny Leung via swift-users
>> <swift-users@swift.org <mailto:swift-users@swift.org>> wrote:
>>
>> Hi All.
>>
>> It seems that if you have an escaping closure argument, you can’t make it
>> optional. Am I right?
>> init (
>> owner:AnyObject,
>> handler:@escaping (HXObserverNotification)->Void
>> ) {
>> self.owner = owner
>> self.handler = handler
>> }
>>
>> You could try this:
>> init (
>> owner:AnyObject,
>> handler:@escaping ((HXObserverNotification)->Void)?
>> ) {
>> self.owner = owner
>> self.handler = handler
>> }
>> You get “@escaping attribute only applies to function types”
>>
>> Or you could try this:
>> init (
>> owner:AnyObject,
>> handler:(@escaping (HXObserverNotification)->Void)?
>> ) {
>> self.owner = owner
>> self.handler = handler
>> }
>> You get “@escaping attribute may only be used in function parameter position”
>>
>> -Kenny
>>
>>
>> _______________________________________________
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>> swift-users@swift.org <mailto:swift-users@swift.org>
>> https://lists.swift.org/mailman/listinfo/swift-users
>
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