Because it would break this:
func foo<T: C, U: A> (c: T, a: U) { c.test(a) }
Nevin
On Wed, Jan 17, 2018 at 2:29 AM, Roshan via swift-users <
[email protected]> wrote:
> Hi,
>
> Here is some sample code that gives a protocol conformance error in a
> playground:
>
> protocol A {}
> protocol B: A {}
>
> protocol C {
> func test(x: A)
> }
>
> class M: C {
> func test(x: B) {}
> }
>
> Is there a reason why the compiler doesn't infer that ((B) -> ())
> matches ((A) -> ()) because of inheritance?
>
> --
> Warm regards
> Roshan
> _______________________________________________
> swift-users mailing list
> [email protected]
> https://lists.swift.org/mailman/listinfo/swift-users
>
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