if (count($this->pager->getNbResults()) == 0 && $this->pager-
>getCurrentPage() <> 1)
{
$this->forward404();
}
But it doesn't work correctly. "<>1" is the same as "!=1" so ???? :)
On 30 Gru, 10:43, Alexandru-Emil Lupu <[email protected]> wrote:
> You could do something else:
>
> $this->pager->init();
> if (count($this->pager->getNbResults()) == 0 &&
> $this->pager->getCurrentPage() <> 1)
> {
> // force the redirect to the first page
>
> }
>
> I have used " <>1 ", because that would cover all the cases of invalid page
> numbers (including -1 page )
>
> Alecs
>
>
>
> On Wed, Dec 30, 2009 at 7:52 AM, dziobacz <[email protected]> wrote:
> > Could somebody add to Symfony Pager code:
>
> > if($request->hasParameter('page') && ((int)$request->getParameter
> > ('page') > $this->pager->getLastPage() ||
> > (int)$request->getParameter('page') < $this->pager->getFirstPage())
> > )
> > $this->forward404();
>
> > because now if for example somebody change url and write number of
> > page > number of all pages he will see only pager ?
>
> > --
>
> > You received this message because you are subscribed to the Google Groups
> > "symfony developers" group.
> > To post to this group, send email to [email protected].
> > To unsubscribe from this group, send email to
> > [email protected]<symfony-devs%[email protected]>
> > .
> > For more options, visit this group at
> >http://groups.google.com/group/symfony-devs?hl=en.
>
> --
> Have a nice day!
> Alecs
>
> As programmers create bigger & better idiot proof programs, so the universe
> creates bigger & better idiots!
> I am on web: http://www.alecslupu.ro/
> I am on twitter:http://twitter.com/alecslupu
> I am on linkedIn:http://www.linkedin.com/in/alecslupu
> Tel: (+4)0748.543.798
--
You received this message because you are subscribed to the Google Groups
"symfony developers" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/symfony-devs?hl=en.