Oh, I see. I don't know if the routing rules work that way or not, I
always thought that anything you defined specifically under param
would override anything that came from the url.
When I've wanted to do things like this in the pass, I would use two
or more different rules:
url: /:mode
param: { module: categories, action: show, category1: 1 }
requirements: { mode: ^(basic|premium) }
url: /:mode/:category1
param: { module: categories, action: show }
requirements: { mode: ^(basic|premium), category1: \d+ }
On 8/31/07, Yeray Rodriguez <[EMAIL PROTECTED]> wrote:
> Hi David,
>
> thanks for your answer. I defined category1 under param to give it a default
> value to avoid another routing rule when there isn't category1 on the url.
>
>
> On 8/31/07, David Brewer <[EMAIL PROTECTED]> wrote:
> >
> > Try this variation on your routing rule:
> >
> > url: /:mode/:category1
> > param: { module: categories, action: show }
> > requirements: { mode: ^(basic|premium), category1: \d+ }
> >
> > You don't need to define settings for the category1 or mode parameters
> > under 'param' as since they are part of the URL, they will
> > automatically get set.
> >
> > David Brewer
> >
> > On 8/31/07, Yeray Rodriguez <[EMAIL PROTECTED] > wrote:
> > >
> > > Hi, I'm using Symfony 1.0.6 and i have a problem con routing
> > >
> > > if i define this rule:
> > >
> > > example:
> > > url: /:mode/:category1
> > > param: { module: categories, action: show, mode: basic, category1:
> > > 1 }
> > > requirements: { mode: ^(basic|premium), category1: \d+ }
> > >
> > > with this url: /premium/2
> > >
> > > i get next:
> > >
> > > $this->getRequestParameter("mode") -> premium
> > > $this->getRequestParameter("category1") -> premium
> (incorrect)
> > >
> > > Debugging sfRouting (parse method) i've found that :
> > >
> > > if (preg_match($regexp, $url, $r)) ....
> > >
> > > $regexp = #^(?:\/((basic|premium)))?(?:\/(\d+))?$#
> > > $url = /premium/2/
> > > $r=Array ( [0] => /premium/2 [1] => ofertas [2] => ofertas [3] => 2 )
> > >
> > > maybe regexp is not well defined?? any idea? Thanks.
> > >
> > >
> > > >
> > >
> >
> >
> >
>
>
>
> --
> "La imaginación puede llevarte a cualquier lado"
>
> >
>
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