Hi every:
I have the following code at preExecute() function:
[code]
public function preExecute()
{
if ( $this->getModuleName() == "geslicsoft") {
$this->mostrar_parcial = "geslicsoft";
}
}
Then in the "layout.php" I have this other code:
[code]
<?php
if (isset($mostrar_parcial)) {
switch ($mostrar_parcial)
{
case "geslicsoft":
include_partial('LicenciasAdminMenu');
break;
}
}
?>
When I execute the action, normally, all is fine and I check using DebugBar and
at the end I can read this:
View -> initialize view for "geslicsoft/_LicenciasAdminMenu"
View -> render "sf_app_dir/modules/geslicsoft/templates/_LicenciasAdminMenu.php"
Now when I validate a form if I leave at least one field blank Symfony never
render the partial again. I try also to force the variable in the handleError
method:
[code]
public function handleErrorAdicionarAutor()
{
$this->mostrar_parcial = "geslicsoft";
return sfView::SUCCESS;
}
I check again using DebugBar and at the end it only wrote this:
Filter -> executing filter "sfFillInFormFilter"
¿Somebody having before this problem and found the solution?
Cheers and thanks in advance
Ing. Reynier Pérez Mira
Grupo Soporte al Desarrollo - Dirección Técnica IP
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"symfony users" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/symfony-users?hl=en
-~----------~----~----~----~------~----~------~--~---