Yeah. You should never, ever program javascript without a runtime
debugger, and Firebug is pretty much the gold standard for Useful and
Versatile.

On Mar 10, 8:06 am, Gareth McCumskey <[email protected]> wrote:
> Are you using Firefox? If so try to get the Firebug add on installed if you
> haven't already and try to use that to see if your Javascript is in fact
> working correctly. It may be hitting an error which you cannot see.
>
> On Tue, Mar 10, 2009 at 1:58 PM, Pooja <[email protected]> wrote:
>
> > hi Yohann
> > i tried using the same code but still problem is not solved.
>
> > On Mar 10, 2:17 pm, Yohann <[email protected]> wrote:
> > > Hi,
>
> > > Try :
>
> > > <div id='display></div>
> > > <?php echo link_to_remote('User Screen',
> > > array('update'=>'display',
> > >         'url'=>'sample/user',
> > >         'script' => true)) ?>
>
> > > The value 'script' in array allows to evaluate JavaScript code in
> > > return a call AJAX.
>
> > > See :
> >http://www.symfony-project.org/book/1_1/11-Ajax-Integration#chapter_1...
>
> > > On 10 mar, 09:39, Pooja <[email protected]> wrote:
>
> > > > Hi
> > > > I am using code below for a link.When link is clicked everything works
> > > > well but javascript code in userSuccess.php is not executed...Plz help
> > > > <div id='display></div>
> > > > <?php echo link_to_remote('User Screen',array
> > > > ('update'=>'display','url'=>'sample/user')) ?>- Hide quoted text -
>
> > > - Show quoted text -
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