Hey Ahmed, look into sfContext::getInstance()->getController()->genUrl ($internal_uri, $absolute); to generate the url. That's what's being called from within the url_for function, and it's perfectly fine to use that within your app code.
Hope this helps, Daniel On Apr 16, 4:26 am, Ahmed <[email protected]> wrote: > Hi paolo ; > I have already done this before but my goal is to separate the all my > Javascript from templates > and use helper in this file . > Best regards Ahmed > > > permuter > > On 16 avr, 13:09, Paolo Mainardi <[email protected]> wrote: > > > Embed this code in a file template and will work :) > > > On Thu, Apr 16, 2009 at 1:08 PM, Ahmed <[email protected]> wrote: > > > > Hi all :) , > > > I want to use a php function to generate url ( for ajax call) in a js > > > file like this : > > > > <?php Header("content-type: application/x-javascript"); ?> > > > $(document).ready(function(){ > > > $.ajax({ > > > url: "<?php echo url_for('company/step1')?>", > > > success: function(html){ > > > $("#step1_container").append(html); > > > } > > > }); > > > }) ; > > > > But in the generated code i have a logic error > > > $(document).ready(function(){ > > > 2 $.ajax({ > > > 3 url: "<br /> > > > 4<b>Fatal error</b>: Call to undefined function url_for() in <b>.... > > > \www\web\js\company\home.js.php</b> on line <b>4</b><br /> > > > > How can i resolve this please ? > > > > [Updated on: Thu, 16 April 2009 12:39] > > > -- > > Paolo Mainardi > > > CTO Twinbit > > Blog:http://www.paolomainardi.com --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "symfony users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en -~----------~----~----~----~------~----~------~--~---
