Try this for adding an object's PARENT form to the child form.
http://www.symfony-project.org/blog/2008/11/07/new-in-symfony-1-2-doctrine-goodies

Where it says "Edit/Add Author" Exactly in the middle of the document.

Me, I'm looking to add Chidren to the Parent Object, but not a large
quanity of them like this guy did:
http://www.thatsquality.com/articles/can-the-symfony-forms-framework-be-domesticated-a-simple-todo-list

Also, he had to go to a lot of trouble to get it to work.

There's got to be a way to add the children, or a blank one without
going to the trouble that he went tol.


(doctrine btw)
ParticularForm extends BaseParticularForm{

function configuration(){
  $this->getObject()->getRelatedObjectForm

On Oct 5, 11:20 pm, Francisco José Núñez Rivera <[email protected]>
wrote:
> I tried it with
>
> $opinion = new Opinion();
> $opfeat = new $opinion->OpinionFeature;
>
> but cant find the class OpinionFeature...
>
> Otherwise i do the same you write (more or less). I think that when i'm
> showing opinion form it creates a new Opinion(); variable.
> Then i use that variable to set the new OpinionFeature var...
> $opfeat->setOpinionId($this->getObject()->id);
> $opfeat->setFeatureId($feature->getId());
>
> $OFform = new OpinionFeatureForm($opfeat);
> $this->embedForm('feature_'.$feature->getId(), $OFform);
>
> But it doesnt work... i have to overwrite saveEmbedForms....
>
> public function saveEmbeddedForms($con = null, $forms = null)
>   {
>
>         foreach($this->getEmbeddedForms() as $opinionForm)
>         {
>
> $opinionForm->getObject()->setOpinionId($this->getObject()->getId());
>         }
>
>     parent::saveEmbeddedForms($con, $forms);
>   }
>
> I think there's a easier way to do this but.. i dont know. :(
>
> 2009/10/6 Dennis <[email protected]>
>
>
>
> > I got this off of a Fabien post, somewhere. If you look at it, it
> > makes everything connect to the same parent record. It SHOULD save
> > correctly. I am goin to try it in my project tonight. Let me know if
> > it works for you.
>
> > $user = new User();
> > $profile = new $user->Profile;
> > $userForm = new UserForm($user);
> > $profileForm = new ProfileForm($profile);
> > $userForm->embedForm('Profile', $profileForm);
>
> > On Oct 5, 2:13 am, elkrema <[email protected]> wrote:
> > > Hi Dennis,
>
> > > there is my schema:
>
> > > Feature:
> > >   tableName: feature
> > >   columns:
> > >     id:
> > >       type: integer(8)
> > >       primary: true
> > >       autoincrement: true
> > >     name:
> > >       type: string(255)
> > >       notnull: true
> > >     created_at: timestamp(25)
> > >     updated_at: timestamp(25)
> > >   relations:
> > >     OpinionFeature:
> > >       local: id
> > >       foreign: feature_id
> > >       type: many
>
> > > Opinion:
> > >   tableName: opinion
> > >   columns:
> > >     id:
> > >       type: integer(8)
> > >       primary: true
> > >       autoincrement: true
> > >     title:
> > >       type: string(255)
> > >       notnull: true
> > >     opiniontxt:
> > >       type: string(2147483647)
> > >       notnull: true
> > >     is_active:
> > >       type: integer(1)
> > >       default: '0'
> > >       notnull: true
> > >     token:
> > >       type: string(255)
> > >       notnull: true
> > >     created_at: timestamp(25)
> > >     updated_at: timestamp(25)
> > >   relations:
> > >     OpinionFeature:
> > >       local: id
> > >       foreign: opinion_id
> > >       type: many
>
> > > OpinionFeature:
> > >   tableName: opinion_feature
> > >   columns:
> > >     opinion_id:
> > >       type: integer(8)
> > >       primary: true
> > >     feature_id:
> > >       type: integer(8)
> > >       primary: true
> > >     score:
> > >       type: float(2147483647)
> > >       notnull: true
> > >     created_at: timestamp(25)
> > >     updated_at: timestamp(25)
> > >   relations:
> > >     Opinion:
> > >       local: opinion_id
> > >       foreign: id
> > >       type: one
> > >     Feature:
> > >       local: feature_id
> > >       foreign: id
> > >       type: one
>
> > > Its very similar to your schema. Mine havent got foreign_type but i
> > > think it works same yours... no?
>
> > > I did that with mysql workbench and then build schema... :)
>
> > > I think the problem was save embed forms i have to overwrite the
> > > saveEmbedForms function to set the opinionid of the OpinionFeature
> > > just at the moment of insert the opinion. Doing that it works, but i
> > > dont know if its the right way.
>
> > > Thank you very much.
>
> > > On 5 oct, 05:10, Dennis <[email protected]> wrote:
>
> > > > So what you have is a:
>
> > > > <Opinion>--1-to-many --<OpinionFeature>--many-to-1--<Feature>
>
> > > > (above is a good way to show a schema)
>
> > > > So you have to set up your schema to reflect that:
>
> > > > Keep in mind that you have to create the Parents, before creating the
> > > > children.
> > > > Parents HAVE an ID, Children are GIVEN or USE and ID.
>
> > > > Parents are 'Opinion' and 'Feature'.
>
> > > > Opinion:
> > > >   tableName: opinion
> > > >   columns:
> > > >     opinion_id:
> > > >       type: integer(8)
> > > >       primary: true
> > > >       sequence: opinion_opinion_id
> > > >     opinion_name:
> > > >       type: string(65)
> > > >       notnull: true
> > > >   relations:
> > > >     OpinionFeature:
> > > >       local: opinion_id
> > > >       foreign: opinion_id
> > > >       type: many
> > > >       foreignType: one
>
> > > > Feature:
> > > >   tableName: feature
> > > >   columns:
> > > >     feature_id:
> > > >       type: integer(8)
> > > >       primary: true
> > > >       sequence: feature_feature_id
> > > >     feature_name:
> > > >       type: string(32)
> > > >       notnull: true
> > > >     feature_desc:
> > > >       type: string(128)
> > > >       notnull: true
> > > >   relations:
> > > >     OpinionFeature:
> > > >       local: feature_id
> > > >       foreign: feature_id
> > > >       type: many
> > > >       foreignType: one
>
> > > > OpinionFeature:
> > > >   tableName: opinionfeature
> > > >   columns:
> > > >     opinion_id:
> > > >       type: integer(8)
> > > >       primary: true
> > > >     feature_id:
> > > >       type: integer(8)
> > > >       primary: true
> > > >     score:
> > > >       type: integer(2)
> > > >       notnull: true
> > > >   relations:
> > > >     Opinion:
> > > >       local: opinion_id
> > > >       foreign: opinion_id
> > > >       type: one
> > > >       foreignType: many
> > > >     Feature:
> > > >       local: feature_id
> > > >       foreign: feature_id
> > > >       type: one
> > > >       foreignType: many
>
> > > >  See if this works :-)
>
> > > > Personally, I like graphical database design tools. I make the design,
> > > > have it spit out the code for the database that I'm using, then make
> > > > the database, use Doctrine to build the schema (instead of composing
> > > > it like above), make my model-forms-filters, and go.
>
> > > > I've had good luck using DezignForDatabases. The guy who makes it is
> > > > very helpful and friendly. It's not perfect, but it's great for the
> > > > price.
> > > > On Oct 2, 3:39 am, Francisco José Núñez Rivera <[email protected]>
> > > > wrote:
>
> > > > > But all the opinions have the same features.
>
> > > > > Feature -> id , desc
> > > > > 1,Feature 1 ; 2, Feature2...
>
> > > > > Opinion shows all the features..
> > > > > Feature 1 -Score:
> > > > > Feature 2 - Score:
>
> > > > > OpinionFeature -> opinion_id , feature_id , score
> > > > > I only insert a row here when im scoring a feature.
>
> > > > > I think my schema is right... no?
>
> > > > > Thank you very much.
>
> > > > > 2009/10/1 Abraham Montilla <[email protected]>
>
> > > > > > elkrema, if you have I have an Opinion with many Features then the
> > right
> > > > > > schema is
>
> > > > > > Feature is: id, opinion_id, desc
> > > > > > OpinionFeature is: opinion_id, score
>
> > > > > > that's why you have an integrity constraint violation.... I don't
> > know how
> > > > > > i missed that first time i read your post hehe, that's all the
> > problem
>
> > > > > > 2009/10/1 elkrema <[email protected]>
>
> > > > > >> With unsetting only option id doesn't work.
>
> > > > > >> The problem is that i am inserting the object of main form and the
> > > > > >> embedded objects too.
>
> > > > > >> But i found a solution... I rewrite the function saveEmbeddedForms
> > in
> > > > > >> OpinionForm
>
> > > > > >>  public function saveEmbeddedForms($con = null, $forms = null)
> > > > > >>  {
>
> > > > > >>                foreach($this->getEmbeddedForms() as $opinionForm)
> > > > > >>                {
>
> > > > > >>  $opinionForm->getObject()->setOpinionId($this->getObject()->getId
> > > > > >> ());
> > > > > >>                }
>
> > > > > >>        parent::saveEmbeddedForms($con, $forms);
> > > > > >>  }
>
> > > > > >> I set the opinionid before saving the embed forms....I dont know
> > if is
> > > > > >> the good way..
>
> > > > > >> Otherwise i have a new problem..
>
> > > > > >> when i'm editing an opinion the value of the last feature is not
> > > > > >> showed.. ¿?
>
> > > > > >> Thank you!
>
> > > > > >> On 30 sep, 07:21, Abraham Montilla <[email protected]> wrote:
> > > > > >> > try just unsetting opinion_id, tell me if works
>
> > > > > >> > 2009/9/29 elkrema <[email protected]>
>
> > > > > >> > > Hello Abraham,
>
> > > > > >> > > This is my code with i'm embedding forms in OpinionForm:
>
> > > > > >> > > foreach($this->getObject()->getFeatures() as $feature)
> > > > > >> > > {
> > > > > >> > >  $opinionf = new OpinionFeature();
> > > > > >> > >  $opinionf->setOpinionId($this->getObject()->id);
> > > > > >> > >  $opinionf->setFeatureId($feature->getId());
> > > > > >> > >  $this->embedForm($feature->getName(), new OpinionFeatureForm
> > > > > >> > > ($opinionf));
> > > > > >> > > }
>
> > > > > >> > > With this code in when saving always get this flash message in
> > the
> > > > > >> > > first Feature...
>
> > > > > >> > >    * Feature id: Invalid.
>
> > > > > >> > > And if i configure OpinionFeatureForm to unset the fields
> > (just for
> > > > > >> > > testing)
>
> > > > > >> > >    unset($this['opinion_id'], $this['feature_id']);
>
> > > > > >> > > I get ..
>
> > > > > >> > > SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot
> > add or
> > > > > >> > > update a child row: a foreign key constraint fails
> > > > > >> > > (`opinion`.`opinion_feature`, CONSTRAINT
> > `opinion_feature_ibfk_1`
> > > > > >> > > FOREIGN KEY (`opinion_id`) REFERENCES `opinion` (`id`) ON
> > DELETE
> > > > > >> > > CASCADE)
>
> > > > > >> > > Thank you for helping
>
> > > > > >> > > On 29 sep, 01:25, Abraham Montilla <[email protected]>
> > wrote:
> > > > > >> > > > i think it's because when embedding the OpinionFeatureForms
> > you're
> > > > > >> not
> > > > > >> > > > setting properly the foreign key to the objects, would be
> > something
> > > > > >> like
>
> > > > > >> > > > for ( $i  ..... ){
> > > > > >> > > > $opfeat = new OpinionFeature();
> > > > > >> > > > $opfeat->setOpinionId($this->getObject->getId());
> > > > > >> > > > $OFform = new OpinionFeatureForm($opfeat);
> > > > > >> > > > $this->embedForm('Feature_'.$i, $OFform);
>
> > > > > >> > > > }
>
> > > > > >> > > > 2009/9/28 elkrema <[email protected]>
>
> > > > > >> > > > > Hello
>
> > > > > >> > > > > i have some problems with my embed forms and i can't find
> > a
> > > > > >> > > > > solution...
>
> > > > > >> > > > > I have an Opinion with many Features..
>
> > > > > >> > > > > Feature is: id, desc
> > > > > >> > > > > OpinionFeature is: opinion_id, feature_id,score
>
> > > > > >> > > > > In OpinionForm i'm inserting with [for each] all the
> > features, but
> > > > > >> > > > > when im creating a new opinion i always get [Integrity
> > constraint
> > > > > >> > > > > violation]
>
> > > > > >> > > > > I'ts easy get the id of the feature but i can get the ID
> > of the
> > > > > >> > > > > opinion because it isnt created yet... is null.
>
> > > > > >> > > > > Somebody can help me please? I get trought many forums and
> > jobeet
> > > > > >> > > > > tutorial but i cant get the solution!
>
> > > > > >> > > > > PS. Sorry for me english!!
>
> > > > > >> > > > --
> > > > > >> > > > Have a nice day.
> > > > > >> > > > Abraham Montilla.
>
> > > > > >> > --
> > > > > >> > Have a nice day.
> > > > > >> > Abraham Montilla.
>
> > > > > > --
> > > > > > Have a nice day.
> > > > > > Abraham Montilla.
>
>
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