Stefan, thank you.. and for the ajax validation?

On Wed, Feb 10, 2010 at 1:10 AM, Stefan Paschke
<[email protected]>wrote:

> Hi Samuel
>
> this is pretty straightforward. Install the sfJqueryReloaded plugin for the
> jQuery functionality. This gives you the jq_link_to_remote() and
> jq_form_remote_tag() functions (that actually replace previous prototype
> functions from symfony 1.0). Both functions are wrappers to jQuery.ajax, the
> parameters allow you to specify the id of a html element that you wish to
> replace with the return of the ajax calls. For the actions, you just create
> regular symfony actions. Instead of returning a view in a separate
> success.php file, you can return the view from the action, with
>
> return $this->renderPartial( 'module/partial', array( 'param' => $param )
> );
>
> This is documented nicely somewhere, but I forgot where :-) Now to submit
> the form and add a new entry to the list, I usually reload the entire block
> that contains list and form, with the new entry added to the list, and an
> empty form. To delete an entry from the from, you could just replace the
> block that contains the form. Sometimes, it may also be appropriate to write
> a jQuery function that removes one row from the list and sends a delete call
> to the server which is not answered.
>
> regards
>
> Stefan
>
>
> On Feb 10, 2010, at 5:48 AM, Samuel Morhaim wrote:
>
> > Absalon, thank you..  this shed some light...  and I got part of it
> working, however I am still having issues.
> >
> > I managed to display the list and the form on the same screen, and
> submiting it side by side, it adds a new record to the table (by refreshing
> the entire page.. )
> >
> > I still have issues how to execute the remote and also, how to do ajax
> validations.  Using Symfony 1.4.
> >
> > It seems since they removed it remote on 1.4, and the manual doesn't talk
> much about it its hard to find information (at least for me).
> >
> > Anyone?
> >
> > Thank you.
>
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