Thank you for taking time to help me.

My code is now:


$this->form = new sfForm();
$this->form->setWidgets(array(


 'section_id' => new sfWidgetFormChoice(array(
   'model'  => 'sectors',
   'column' => 'sectorTitle'
 )
)));


But I still get another error: sfWidgetFormChoice does not support the
following options: 'model', 'column'.

Anymore ideas ?

On Nov 12, 12:06 am, Alexandre Salomé <[email protected]>
wrote:
> Add new before sfWidget... : you are instanciating an object, not calling a
> function
>
> ---
> Alexandre Salomé -http://alexandre-salome.fr
>
> Le 12 nov. 2010 01:04, "[email protected]" <[email protected]> a
> écrit :
>
> All I am trying to do is make a drop down menu from a table in a
> database.
> I think I need to place some code in an action class.
>
> The table is called   'sectors.
> The column I would like to see in the drop down menu is  is
> 'sectorTitle'
> '
> The code I am using is:
>
> $this->form = new sfForm();
> $this->form->setWidgets(array(
>
>  'section_id' => sfWidgetFormChoice(array(
>    'model'  => 'sectors',
>    'column' => 'sectorTitle'
>  )
> )));
>
> But I get an error message saying :
>
> Call to undefined function sfWidgetFormChoice()
>
> Does anyone know what I am doing wrong ?
>
> Thanks Reto
>
> --
> If you want to report a vulnerability issue on symfony, please send it to
> security at symfony-project.com
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