I was thinking more along the lines of
$a = BankUserTable::getInstance()->findOneByUserId($user_id);
$a->bank_branch_id = $bank_branch_id;
$a->save();
As far as I understand doctrine internals, you need to create a
version of versionable that extends Doctrine_Record_Listener, and
implement the preDqlUpdate function. Never did this, so can't help you
there. Unless you're updating a lot of objects in a batch, you're
better off using the code above.
--mrl
On Thu, Jun 9, 2011 at 12:44, RYadav <yadavrajesh25j...@gmail.com> wrote:
> @Gabor,
> yes you are right if i wrote like this
>
> $a =new Bank;
> $a->set('bank_name', "'yadav'")
> ->save();
>
> its insert a new record and make its version also, how can i make a
> versional listener for dql.
>
> On Jun 9, 2:53 pm, Gábor Fási <maerl...@gmail.com> wrote:
>> Doctrine's Versionable behavior has no dql update listener. Retrieve
>> the BankUser object first, update and save that and it'll work.
>>
>> On Thu, Jun 9, 2011 at 06:47, Raju <yadavrajesh25j...@gmail.com> wrote:
>> > hi ,
>>
>> > versionable not working on this query
>>
>> > public function updateUserBankBranch($userid,$bank_branch_id){
>> > $q = $this->createQuery()
>> > ->update('BankUser b')
>> > ->set('b.bank_branch_id', $bank_branch_id)
>> > ->where("b.user_id = '$userid'")
>> > ->execute();
>> > return true;
>> > }
>>
>> > while versioning working on symfony generated module can someone help
>> > me on this
>>
>> > --
>> > If you want to report a vulnerability issue on symfony, please send it to
>> > security at symfony-project.com
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>
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