Comment #5 on issue 1471 by [email protected]:
integrate(1/(x**3+1),(x,0,oo)) return an expression with x
http://code.google.com/p/sympy/issues/detail?id=1471
Oops! The 'results' list was a leftover from my initial draft. More
importantly, I
realised that I had introduced a severe performance regression in some
cases.
Before:
In [3]: %timeit limit(exp(x)+exp(x**2), x, oo)
1000 loops, best of 3: 350 µs per loop
In [4]: %timeit limit(exp(x)+exp(x**2) + 1/x, x, oo)
1000 loops, best of 3: 235 µs per loop
In [5]: %timeit limit(exp(x), x, oo)
100 loops, best of 3: 8.72 ms per loop
With the previous version:
In [3]: %timeit limit(exp(x)+exp(x**2), x, oo)
10 loops, best of 3: 24.8 ms per loop
In [4]: %timeit limit(exp(x)+exp(x**2) + 1/x, x, oo)
10 loops, best of 3: 25 ms per loop
In [5]: %timeit limit(exp(x), x, oo)
100 loops, best of 3: 8.79 ms per loop
With the new version:
In [3]: %timeit limit(exp(x)+exp(x**2), x, oo)
1000 loops, best of 3: 197 µs per loop
In [4]: %timeit limit(exp(x)+exp(x**2) + 1/x, x, oo)
1000 loops, best of 3: 271 µs per loop
In [5]: %timeit limit(exp(x), x, oo)
100 loops, best of 3: 8.8 ms per loop
Attachments:
0001-Compute-the-finite-parts-of-the-limit-of-a-sum-by-di.patch 2.4 KB
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