Comment #3 on issue 2247 by [email protected]: Problem with coth http://code.google.com/p/sympy/issues/detail?id=2247
There's no foliation in these cases so there's no need in cuts of Rieman surface:
tanh(acoth(x))=1/x coth(atanh(x))=1/x coth(acoth(x))=x The others is agreed with sqrt foliation, because sqrt(4) 2 Let's proove this formula coth(asinh(x))=sqrt(x**2+1)/x asinh(x)=t so by definition sinh(t)=x coth(t)**2=cosh(t)**2/sinh(t)**2=(1+sinh(t)**2)/sinh(t)**2=(1+x**2)/x**2 as positive branch of sqrt are chosen than coth(t)=sqrt(1+x**2)/x So it seems we should not think about issue's 564 agreement. Sorry if I present too much details. -- You received this message because you are subscribed to the Google Groups "sympy-issues" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy-issues?hl=en.
