Comment #2 on issue 2283 by [email protected]: Non-iterative 'in'
http://code.google.com/p/sympy/issues/detail?id=2283

One possible way would be check in all possible combinations of the expr. for an expr with n simple args, the number of such combinations is exponential 2**n, I think. Checking for what in all of them wouldn't be very efficient.

Another way is to check one by one, and then if all the expr are present in the given expr, then check if they are in the same level. This is a better method, but coding it might be tough.

Hector, have you made any progress to resolve this issue yet ?

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