Comment #1 on issue 2305 by [email protected]: Integer(3).sqrt() == 1 http://code.google.com/p/sympy/issues/detail?id=2305
The docstring says: """Compute integer square root of `a`.""" It also uses an isqrt function from mpmath.
Perhaps the method should be renamed to isqrt -- You received this message because you are subscribed to the Google Groups "sympy-issues" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy-issues?hl=en.
