Updates:
Summary: Integer(3).sqrt() == 1 (Rename Integer.sqrt to Integer.isqrt)
Comment #2 on issue 2305 by asmeurer: Integer(3).sqrt() == 1 (Rename
Integer.sqrt to Integer.isqrt)
http://code.google.com/p/sympy/issues/detail?id=2305
I think it should just be renamed to isqrt. Apparently, that is an actual
thing. See http://en.wikipedia.org/wiki/Integer_square_root.
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