Comment #1 on issue 2343 by [email protected]: as_poly returns None
http://code.google.com/p/sympy/issues/detail?id=2343
Can you show how you construct q1? A simple session with isympy gives me
this:
In [1]: f = -1 + (S(1)/2 - x/2)**2 + (S(1)/3 - y/3)**2
In [2]: f
Out[2]:
2 2
⎛1 x⎞ ⎛1 y⎞
-1 + ⎜─ - ─⎟ + ⎜─ - ─⎟
⎝2 2⎠ ⎝3 3⎠
In [3]: Poly(f)
Out[3]: Poly(1/4*x**2 - 1/2*x + 1/9*y**2 - 2/9*y - 23/36, x, y, domain='QQ')
In [4]: f.as_poly()
Out[4]: Poly(1/4*x**2 - 1/2*x + 1/9*y**2 - 2/9*y - 23/36, x, y, domain='QQ')
In [5]: f.as_poly(x, y)
Out[5]: Poly(1/4*x**2 - 1/2*x + 1/9*y**2 - 2/9*y - 23/36, x, y, domain='QQ')
So it works for me.
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