Comment #3 on issue 2327 by asmeurer: sqrt(I) should return sqrt(2)/2 + sqrt(2)/2*I by default
http://code.google.com/p/sympy/issues/detail?id=2327
So you are *probably* right. It's ironic, since I am usually the stickler about automatic evaluation around here. But I was a little annoyed at it when I was using it for some assignment.
But also consider that I is a number, and we usually *do* automatically evaluate numbers when we can. We would not check if the arg is complex, but if it is a number.
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