Status: Accepted
Owner: asmeurer
CC: [email protected]
Labels: Type-Defect Priority-Medium
New issue 2501 by asmeurer: diff(f(g(x)), x) gives a strange answer
http://code.google.com/p/sympy/issues/detail?id=2501
In [4]: diff(f(g(x)), x)
Out[4]:
d ⎛d ⎞│
──(g(x))⋅⎜──(f(1))⎟│
dx ⎝d1 ⎠│1=g(x)
Maybe I just missed the memo on how differentiation at a point works. Is 1
supposed to be a dummy variable? If so, think it's a bad way, as it's very
confusing.
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