Comment #1 on issue 2557 by brad.froehle: inline Piecewise C code
constructs not actually valid C
http://code.google.com/p/sympy/issues/detail?id=2557
One immediate problem here is how to handle the situation where the
condition for the last entry of Piecewise is not True. I suggest then
using NAN to handle that case. The implementation could be as simple as
def _print_Piecewise(self, expr):
# This method is called only for inline if constructs
# Top level piecewise is handled in doprint()
if expr.args[-1].cond == True:
code = self._print(expr.args[-1].expr)
last = -1
else:
code = "NAN"
last = None
for e,c in reversed(expr.args[:last]):
code = "((%s) ? (%s) : (%s))" % (self._print(c), \
self._print(e), code)
return code
--
You received this message because you are subscribed to the Google Groups
"sympy-issues" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/sympy-issues?hl=en.
