Comment #33 on issue 2607 by [email protected]: as_numer_denom() is too slow
http://code.google.com/p/sympy/issues/detail?id=2607
The unevaluated Mul is a very nice way to go unless you think that
`Mul(2,x, evaluate=False)/2` should not be `x`. If you don't like the final
touching iwth `+0` of the denominator you can `Mul(*Mul.make_args(den))` or
just return the unevaluated Mul. Those changes (as_numer_denom4b) and my
best shot at the expanded results with collection of common denominators
and processing of Integer denominators (as_numer_denom5) are in the "and"
branch of mine.
>>> from sympy.abc import *
>>> from sympy import *
>>> a=x/2 + 1/(5*(x + 1))
>>> a.as_numer_denom()
(x*(5*x + 5) + 2, 10*x + 10)
>>> a.as_numer_denom4()
(x*(10*x + 10)/2 + (10*x + 10)/(5*x + 5), 10*x + 10)
>>> a.as_numer_denom4b()
(x*(5*x + 5) + 2, 2*(5*x + 5))
>>> a.as_numer_denom5()
(x*(5*x + 5) + 2, 10*x + 10)
>>> a=(x/2+1/(x+1)+2)
>>> a.as_numer_denom()
(x*(x + 1) + 4*x + 6, 2*x + 2)
>>> a.as_numer_denom4()
(x*(2*x + 2)/2 + 4*x + 4 + (2*x + 2)/(x + 1), 2*x + 2)
>>> a.as_numer_denom4b()
(x*(x + 1) + 4*x + 6, 2*(x + 1))
>>> a.as_numer_denom5()
(x*(x + 1) + 4*x + 6, 2*x + 2)
>>>
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