Comment #4 on issue 2802 by [email protected]: solve error with expression with derivative
http://code.google.com/p/sympy/issues/detail?id=2802
How does this look? sympy\solvers\solvers.py:541: UserWarning: Note: there is an ode module that offers several functions for handling this sort of equation, including a dsolve function that can be used rather than solve. ''')) [C1] f(x) == C1 [(2*C2 - 3*exp(2*t))*exp(-2*t)/2] The solution could not be validated: when <[C1*exp(-2*t)]> was substituted into the original equation, <g(t)> was obtained. If you want the solution anyway use the flag 'check=False'. [] The solution could not be validated: when <[C1*exp(-2*t)]> was substituted into the original equation, <g(t)> was obtained. If you want the solution anyway use the flag 'check=False'. [] [C1*exp(-2*t)] f(t) == C1*exp(-2*t) [-sqrt((x + 2)**2*exp(-2*C1) + 1), sqrt((x + 2)**2*exp(-2*C1) + 1)] -log(f(x)**2 - 1)/2 == C1 - log(x + 2) btw, for some reason sometimes I get a different solution for the equation you gave, e.g.: [exp(2*C1 - 2*t)/2 - 3/2] The solution could not be validated: when <f(t) == (C1 - g(t)*exp(2*t)/2)*exp(-2*t)> was substituted into the original equation, <-Derivative(g(t), t)> was obtained. If you want the solution anyway use the flag 'check=False'. -- You received this message because you are subscribed to the Google Groups "sympy-issues" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy-issues?hl=en.
