Comment #2 on issue 3108 by [email protected]: wrong code in
Polygon.arbitrary_point
http://code.google.com/p/sympy/issues/detail?id=3108
It only works with built-in types (and sympy types that emulate them).
1 < x < 0
x < 0
Roughly, Python interprets "x < y < z" as "(x < y) and (y < z)",
where "and" is the built-in operator. Since symbolic objects are true-ish,
the latter expression evaluates to just "y < z".
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