Comment #12 on issue 1092 by [email protected]: limit(sum(1/k, (k, 1,
n))-log(n), n, oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
This now returns
limit(summation(1/k, (k, 1, n))-log(n), n, oo)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "sympy\series\limits.py", line 216, in limit
r = heuristics(e, z, z0, dir)
File "sympy\series\limits.py", line 221, in heuristics
return limit(e.subs(z, 1/z), z, S.Zero, "+" if z0 is S.Infinity
else "-")
File "sympy\series\limits.py", line 216, in limit
r = heuristics(e, z, z0, dir)
File "sympy\series\limits.py", line 239, in heuristics
raise PoleError(msg % (e, z, z0, dir))
sympy.core.function.PoleError: Don't know how to calculate the
limit(-log(1/n) +
harmonic(1/n), n, 0, dir=+), sorry.
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