Status: New
Owner: ----
Labels: Type-Defect Priority-Medium
New issue 3308 by [email protected]: integrate a derivative with a
substituted argument
http://code.google.com/p/sympy/issues/detail?id=3308
Defining
f = symbols('f', cls=Function)
t, x = symbols('t x')
Sympy is not able to apply the fundamental theorem of calculus when the
integrand is a derivative with a substituted argument.
(bug report related to
https://groups.google.com/d/topic/sympy/v7XTpoxWqEc/discussion)
As pointed out by Aaron,
integrate(f(t).diff(t), (t, 0 , x))
works fine and gives (f(x) - f(0)), while
integrate(subs(f(x).diff(x), x), x, x - t), (t, 0, x)))
should also be supported by integrate since the answer (f(x) - f(0)) is
computable
Best,
Pierre
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