Updates:
Labels: -CodeInDifficulty-Hard
Comment #7 on issue 2789 by [email protected]: minpoly should work with
roots of unity in exponential form
http://code.google.com/p/sympy/issues/detail?id=2789
The math here is hard, but I think that if you can understand it, that it's
not too difficult. All you need to do add a case to the code to mark the
polynomial for exp(a/b*2*I*pi) as x**b - 1.
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