Comment #7 on issue 3716 by [email protected]: Integrals over non-interval
sets
http://code.google.com/p/sympy/issues/detail?id=3716
The real issue is that Interval(b, a) represents the empty set when b > a
but Integral(f(x), (x, b, a)) = -Integral(f(x), (x, a, b)). The best I can
think of to work around this is to use Piecewise, but that gets messy for
more than two intervals.
Currently we just return 0
That's because integrate exits early if the upper limit equals the lower
limit. This might not actually be right.
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