Comment #4 on issue 3837 by [email protected]: RootOf.free_symbols gives
wrong result
http://code.google.com/p/sympy/issues/detail?id=3837
RootOf.free_symbols uses the poly method to get the underlying polynomial.
If a PurePoly is returned, it will give the null set for free symbols (if
it is univariate). Using sol above:
sol[0]
RootOf(x**3 + 4*x + 1, 0)
_.poly
Poly(x**3 + 4*x + 1, x, domain='ZZ')
vs
RootOf(y**3 +5*y + 1, 0)
RootOf(y**3 + 5*y + 1, 0)
_.poly
PurePoly(y**3 + 5*y + 1, y, domain='ZZ')
So the question is "Why does poly give a PurePoly in one case but not the
other?"
--
You received this message because this project is configured to send all
issue notifications to this address.
You may adjust your notification preferences at:
https://code.google.com/hosting/settings
--
You received this message because you are subscribed to the Google Groups
"sympy-issues" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To post to this group, send email to [email protected].
Visit this group at http://groups.google.com/group/sympy-issues?hl=en.
For more options, visit https://groups.google.com/groups/opt_out.
