Comment #6 on issue 4002 by [email protected]: Factorizing rational
functions
http://code.google.com/p/sympy/issues/detail?id=4002
I think the factoring is done the other way round. So if you had something
like (z+a)*(z+b) making a factor(z) you got z**2+(a+b)*z+a*b, which is the
one shown in the numerator. At least this was the result in version 0.7.2,
and the one got if you have any kind of polynomial. This is not the case
for a division between to polynomials.
Said in other words:
(z+a)*(z+b)/(z+c)/(z+d) in 0.7.2 gave the result:
(z**2+(a+b)*z+a*b)/(z**2+(c+d)*z+c*d), at least is what I got with
different formulas.
But from your words, I understand that this was not the expected behavior.
So I have searched a workaround...
f = fraction((z+a)*(z+b)/(z+c)/(z+d))
f[0].expand().collect(z)/f[1].expand().collect(z)
It seems to work as desired.
Thanks for your help,
Jose M.
El 04/09/2013, a las 19:40, [email protected] escribi�:
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