Comment #22 on issue 1932 by [email protected]: Relationals do not work with
any methods of Expr
http://code.google.com/p/sympy/issues/detail?id=1932
OK, here a slightly modified `do` function that doesn't use the applyfunc.
def do(self, e, i=None):
"""do `e` to both sides of self using function given or
model expression with a variable representing each side:
>> eq.do(i + 2) # add 2 to both sides of Equality
>> eq.do(i + a, i) # add `a` to both sides; 3rd parameter identifies
`i`
>> eq.do(lambda i: i + a) # modification given as a function
"""
if isinstance(e, (FunctionClass, Lambda, type(lambda:1))):
return self.applyfunc(e)
e = S(e)
i = (set([i]) if i else e.free_symbols) - self.free_symbols
if len(i) != 1:
raise ValueError('not sure what symbol is being used to represent a
side')
i = i.pop()
f = lambda side: e.subs(i, side)
return self.func(*[f(side) for side in self.args])
from sympy.core.relational import Equality
Equality.do = do
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