luis wrote:
> Hello Alan,
>
> Thanks for your answer. Apparently all I need from the exterior
> algebra
> can be done with '^'. If so, I can still use, as you suggest, a
> diferent metric in the setup. (I will probably use a euclidien
> metric)
> and then use the geometric product ('*') to compute the dual: "-I*a".
> I will look tomorrow into the Doran and Lasenby.
>
> Regards,
>
> Luis
>
> -----
>
> On Jan 18, 9:32 pm, Alan Bromborsky <[email protected]> wrote:
>   
>> luis wrote:
>>     
>>> Hi,
>>>       
>>> Thanks,
>>>       
>>> Non, I don't want a Minkowsky metric. I am simply doing exterior
>>> algebra in R^4  (or R^n) and in such case I need a null metric
>>> to have the wedge product in Lambda(R^n).
>>>       
>>> As you can see 
>>> inhttp://en.wikipedia.org/wiki/Clifford_algebra#As_quantization_of_exte...
>>> the exterior algebra Lamda(R^n) is the same as Cl(R^n,Q) with Q a null
>>> metric.
>>>       
>>> Do you know another way of 'simulating' the wedge (alternating)
>>> product of the
>>> exterior algebra?
>>>       
>>> Luis
>>>       
>>> ------
>>>       
>>> On Jan 18, 8:19 pm, Alan Bromborsky <[email protected]> wrote:
>>>       
>>>> luis wrote:
>>>>         
>>>>> Hi,
>>>>>           
>>>>> Thanks. Since I want to do exterior algebra, I am using a null
>>>>> metric.
>>>>> Also, I am not in 3-dim and so I don't have a cross product.
>>>>>           
>>>>> Let's suppose we have the following code:
>>>>>           
>>>>> #######################
>>>>> #!/bin/env python
>>>>> from sympy.galgebra.GAsympy import *
>>>>> set_main(sys.modules[__name__])
>>>>> MV.setup('e0 e1 e2 e3', '0 0 0 0, 0 0 0 0, 0 0 0 0, 0 0 0 0')
>>>>> a = e0*e1*e2*e3
>>>>> ######################
>>>>>           
>>>>> We know that in this case
>>>>>           
>>>>> a  = e0^e1^e2^e3              and
>>>>> *a = 1              (one)
>>>>>           
>>>>> but I don't know how to obtain this value (one) with sympy,
>>>>> starting from 'a'. I suspect it should be trivial, but I
>>>>> don't see how to do.
>>>>>           
>>>>> Luis
>>>>>           
>>>>> ---------------------------
>>>>>           
>>>>> On Jan 18, 7:24 pm, Alan Bromborsky <[email protected]> wrote:
>>>>>           
>>>>>> luis wrote:
>>>>>>             
>>>>>>> Hi,
>>>>>>>               
>>>>>>> Is there some way in  'galgebra.GAsympy'
>>>>>>> to apply the Hodge-* operator?
>>>>>>>               
>>>>>>> Thanks,
>>>>>>>               
>>>>>>> Luis
>>>>>>>               
>>>>>>> PS. I am using MV.setup(basis,metric) with a null metric.
>>>>>>>               
>>>>>> Seehttp://en.wikipedia.org/wiki/Geometric_algebra.  I think the Hodge
>>>>>> dual of a vector, v, is just the geometrics product of the vector and
>>>>>> the pseudoscalar I that is
>>>>>>             
>>>>>> v* = v*I
>>>>>>             
>>>>>> for 3-dimensions (signature(+++)) we have the relation that the cross
>>>>>> product of two vectors a and b is
>>>>>>             
>>>>>> a x b = -I a ^ b
>>>>>>             
>>>>>> where I is the pseudo-scalar and ^ is the outer (exterior) product
>>>>>>             
>>>>>>  seehttp://wiki.sympy.org/wiki/Geometric_Algebra_Moduleforhowto set
>>>>>> up your metric.
>>>>>>             
>>>> I think you want (for minkowski metric)
>>>>         
>>>> #!/bin/env python
>>>> from sympy.galgebra.GAsympy import *
>>>> set_main(sys.modules[__name__])
>>>> MV.setup('e0 e1 e2 e3', '1 0 0 0, 0 -1 0 0, 0 0 -1 0, 0 0 0 -1')
>>>>         
>>>> since metric is orthogonal
>>>>         
>>>> a = I = e0*e1*e2*e3
>>>>         
>>>> or
>>>>         
>>>> a = I = e0^e1^e2^e3
>>>>         
>>>> a* = a*I = I*I = +1 or -1 depending on the metric for minkowski metric a*I 
>>>> = -1,
>>>>         
>>>> for 4-dimensional euclidian a*I = 1 (MV.setup('e0 e1 e2 e3', '1 0 0 0, 0 1 
>>>> 0 0, 0 0 1 0, 0 0 0 1'))
>>>>         
>>>> remember that for vectors a,b
>>>>         
>>>> a*b = a.b + a^b
>>>>         
>>>> geometric algebra is a clifford algebra
>>>>         
>>>> for higher dimension rotations let U = a^b where U**2 = -1 (always true in 
>>>> a euclidian space) define the rotation
>>>> plane and theta the ammount of rotation.  The the rotor is
>>>>         
>>>> R = cos(theta/2)+sin(theta/2)U
>>>>         
>>>> and the rotation of a vector x->x' is given by
>>>>         
>>>> x' = R*x*rev(R)  (all geometric products)
>>>>         
>>>> where rev(R) = cos(theta/2)-sin(theta/2)U
>>>>         
>>>> if U**2 = 1 replace cos and sin with cosh and sinh
>>>>         
>> The ^ product of geometric algebra is alternating since a^b = -b^a  and
>> a^a= 0 for vectors regardless of the metric.  Note that the ^
>> (wedge,outer,exterior) product and the | (dot,inner) product are built
>> into GAsympy along with the * (geometric) product.  All are defined for
>> arbitrary multivectors.  If you use ^ or | be sure to use parenthesis
>> since the python operator priority for ^ and | is not what we would use
>> in a geometric algebra expression.  If you have a good library available
>> look at "Geometric Algebra for Physicists" by Doran and Lasenby, page
>> 218.  They show the relationship between geometric calculus and
>> differential forms.  I haven't dealt with differential forms in 30 years
>> so my knowledge about the correspondence with geometric calculus is
>> probably negative.
>>     
> >
>
>   
This link may be usefule to you.

http://www.mrao.cam.ac.uk/~clifford/introduction/intro/node12.html

--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups 
"sympy" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to [email protected]
For more options, visit this group at http://groups.google.com/group/sympy?hl=en
-~----------~----~----~----~------~----~------~--~---

Reply via email to