Another thought:

Make a new diff function and call it pdiff.  The only difference
between diff and pdiff would be that pdiff always returns \partial for
'd'.

Not certain that this suggestion is much different than the
above...developers will know, I'm sure.

Comer

On Mar 23, 3:26 pm, "[email protected]" <[email protected]>
wrote:
> Most of the time I am dealing with PDEs and as such think it would be
> cool if sympy can do the right thing when pprinting an expression
> involving partial derivatives. Currently it's my understanding that
> only the 'd' gets rendered rather than \partial.  So my question is
> whether sympy can be educated to  make the right choice?  As an
> example, here is a simple example of what I get with the current
> convention:
>
> from sympy import *
> from sympy import Symbol
>
> t,x,y,z,v = symbols('txyzv')
>
> phi = Function("rphi")
>
> advectionEQ = phi(t,x,y,z).diff(t) + v * phi(t,x,y,z).diff(x)
>
> pprint(advectionEQ) with the result:
>
>     d                            d
> v⋅──(φ(t, x, y, z)) + ──(φ(t, x, y, z))
>     dx                           dt
>
> As a probably too primitive suggestion, how about having the pprint
> look at the number of independent variables in the above expression
> and if the count is greater than 1 use \partial in place of 'd' ?
>
> Or have the pprint do its usual thing except at the end of its work
> the resulting expression is parsed for d and turned into \partial?
>
> Another thing that  is sort of not beautiful in the above output is
> that the d/dx term is always first even though the object advectionEQ
> has the d/dt in the first term in the expression.  How can I get the
> desired order in the output of the pprinted expression?
>
> Thanks for suggestions/corrections.
>
> Comer
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