I'm using the latest pull from git://git.sympy.org/sympy.git, and this
is the response I get:
In [1]: from sympy import *
In [2]: f, w = symbols('fw')
In [3]: s = 2*pi*I*f
In [4]: ia = (-2*s**2*w**2 + w**4)/(s**4 + w**4)
In [5]: simplify(integrate(ia, (f, 0, infty)))
---------------------------------------------------------------------------
NameError Traceback (most recent call
last)
/home/luke/lib/python/sympy/<ipython console> in <module>()
NameError: name 'infty' is not defined
In [6]: simplify(integrate(ia, (f, 0, oo)))
Out[6]: 0
In [10]: oo.__class__
Out[10]: <class 'sympy.core.numbers.Infinity'>
I'm guessing 'infty' is something you've defined on your own machine
for convenience.
What exactly does it mean to be using the 'trunk'?
Thanks,
~Luke
On May 26, 4:04 pm, Neal Becker <ndbeck...@gmail.com> wrote:
> On Tuesday 26 May 2009, Robert Kern wrote:
>
> > On Tue, May 26, 2009 at 17:04, Neal Becker <ndbeck...@gmail.com> wrote:
> > > On Tuesday 26 May 2009, Robert Kern wrote:
> > >> On Tue, May 26, 2009 at 15:08, Luke <hazelnu...@gmail.com> wrote:
> > >> > I get the same behavior on my machine.
>
> > >> Hmm, I don't.
>
> > > I'm using 0.6.4, are you using something newer perhaps?
>
> > Yes, the trunk.
>
> Here's what maxima says:
>
> (%o33) (w^4+8*%pi^2*f^2*w^2)/(w^4+16*%pi^4*f^4)
>
> (%i35) integrate(%o33,f,0,inf);
> Is w positive or negative? positive;
> (%o35) (3*w)/(4*sqrt(2))
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