> Could you please post an example where this method actually works? For
> radicals I'd choose another strategy (isolating the radical on one
> side of the equation, squaring, solving, checking afterwards for false
> solutions).
>

Now revisiting the problem I guess you're right. If there are two
terms and you can't find a solution for them as they are, you won't
find a solution with their inverses, either. e.g. sin(x)-log(x)=0 If
you can't find a solution for this, you won't be able to find one for
asin(c)=exp(c). I'm not sure how I got on this track of thinking.
Perhaps it was an extension of the idea of finding trivial solutions
for the case where some sum of terms = 0 therefore if you can find an
x that sets each term to 0 then that's a solution. I must have been
thinking that if you could, for two terms, find a value (not
necessarily 0) that would cancel the two terms out then you would have
a solution as well...but if you can find that value then you should be
able to solve the original problem. [hand to forehead]

Now the question of symmetry remains. If you have 3**x-x**3 there is a
lambert solution of 2.478 which is found by inversion but there is
also the solution of x=3...but maybe that is just the other solution
from the -1 branch of lambert. Maybe anything that looks like this but
is actually something else (sin(x)**.5-.5**sin(x) with solution of x=.
5) is just too esoteric to be of siginificance.

/c

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