I have been working on getting separable equations in dsolve, and I
noticed this:
>>> c = Wild('c', exclude=[y])
>>> d = Wild('d', exclude=[x])
>>> (x).match(c*d)
{c: x, d: 1}
>>> (log(x)).match(c*d)
{c: log(x), d: 1}
>>> (x*log(x)).match(c*d)
<Returns None>
I would like for the last one to return {c:x*log(x), d:1}. Presently,
I don't *need* this to work, because there is a workaround I can use
where I multiply the expression by x*y to ensure that it has x's and
y's in it and then they cancel out. But this is kind of hacky, and,
unless I am mistaken, this is not the expected behavior of match. I
searched the issues and I didn't see it, unless I missed it.
Aaron Meurer
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